The average upward force exerted by the water on the diver is 13,043 N.
To solve this problem, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration. We can rearrange this equation to solve for the force: F = m * a.
We know the mass of the diver (m = 65.0 kg) and the time it took for her downward motion to be stopped (t = 2.30 s). We can calculate the acceleration by using the equation a = v/t, where v is the final velocity. Since the diver started from rest, her final velocity is the same as her downward velocity, which is 10.0 m/s. Therefore, a = 10.0 m/s / 2.30 s = 4.35 m/s^2.
Plugging this into the equation F = m * a, we get F = 65.0 kg * 4.35 m/s^2 = 13,043 N.
A high diver of mass 65.0 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If her downward motion is stopped 2.30 s after her feet first touch the water, what average upward force did the water exert on her?
I'm not sure how to go about solving this. I've tried a few different ways but none of them yielded the right answer. Please help.
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