A high diver of mass 70 kg jumps off a diving board and enters the water with the speed of 10 m/s the average upward resistance force of water exerts on the diver is 200 N. How far in the water will the diver travel before coming to rest?

Answer 1

assume hydrostatics is negligible

F = m a
a = 200/70 = 2.86

v = Vi - a t
0 = 10 - 2.86 t
t = 3.5 seconds to stop

d = Vi t - (1/2)(2.86) t^2

d = 10 (3.5) - 1.43 (3.5)^2

d = 35 - 17.5

d = 17.5 meters

well, that is what we get. It is ridiculously high but so be it. Let's hope it is a really, really, deep pool :)