A gun is fired vertically into a 1.60 kg block of wood at rest directly above it. If the bullet has a mass of 21.0 g and a speed of 195 m/s, how high will the block rise into the air after the bullet becomes embedded in it?

Answer 1

initial momentum = .021 *195
final momentum = (.021+1.6)Vi
Vi = 2.53

(1/2) m Vi^2 = m g h
h = Vi^2/2g