a bullet of mass 120g is fired horizontally into a fixed wooden block with a speed of 20 m/s. If the bullet is brought to rest in the block in 0.1s by a constant resistance, calculate the

Question

1) magnitude of the
2) Distance moved by the bullet in the wood.?

Answer 1

a = ∆v/∆t = -20/0.1 = -200 m/s^2
s = vt + 1/2 at^2 = 20*0.1 - 100*0.1^2 = ?

Answer 2

1. V = Vo + a*t = 0.
20 + a*0.1 = 0,
a = -200 m/s^2.
F = M*a = 0.120 * (-200) = -24 N. = opposing resistance.

Answer 3

Thanks but can u break it down for me

Answer 4

Thanks but can you break it for me please

Answer 5

Tnx to but I need it in details please