To find the weight of the water in an Olympic-sized swimming pool, we start with the given values:
- 1 gallon of water weighs approximately 8.3 lb.
- An Olympic-sized swimming pool holds \(6.6 \times 10^5\) gallons.
Now, we can calculate the total weight of the water in the pool:
\[ \text{Total weight} = \text{Weight per gallon} \times \text{Number of gallons} \] \[ \text{Total weight} = 8.3 , \text{lb/gallon} \times (6.6 \times 10^5 , \text{gallons}) \]
Calculating the multiplication:
\[ 8.3 \times 6.6 = 54.78 \]
Now we multiply by \(10^5\):
\[ \text{Total weight} = 54.78 \times 10^5 , \text{lb} \]
Finally, we express this in proper scientific notation. In scientific notation, we want to have only one non-zero digit to the left of the decimal. Therefore, we can convert \(54.78 \times 10^5\) to:
\[ 5.478 \times 10^6 , \text{lb} \]
Thus, the approximate weight of the water in an Olympic-sized swimming pool, in scientific notation, is:
\[ \boxed{5.478 \times 10^6 , \text{lb}} \]
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