Question

A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105%0D%0A6.6%0D%0A×%0D%0A10%0D%0A5%0D%0A gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)%0D%0AResponses%0D%0A%0D%0A5.478×106%0D%0A5.478%0D%0A×%0D%0A10%0D%0A6%0D%0A lb.%0D%0A5 point 4 7 8 times 10 to the 6th power lb.%0D%0A%0D%0A54.78×106%0D%0A54.78%0D%0A×%0D%0A10%0D%0A6%0D%0A lb.%0D%0A54 point 7 8 times 10 to the 6th power lb.%0D%0A%0D%0A54.78×105%0D%0A54.78%0D%0A×%0D%0A10%0D%0A5%0D%0A lb.%0D%0A54 point 7 8 times 10 to the 5th power lb.%0D%0A%0D%0A5.478×105%0D%0A5.478%0D%0A×%0D%0A10%0D%0A5%0D%0A lb.

Answer 1

To find the weight of the water in an Olympic-sized swimming pool, we first need to calculate the volume in gallons and then convert that to weight in pounds.

1. Volume of the pool in gallons: The volume of an Olympic-sized swimming pool is given as \( 6.6 \times 10^5 \) gallons.

2. Weight per gallon: Each gallon of water weighs approximately 8.3 pounds.

3. Total weight: To find the total weight of the water in the pool: \[ \text{Total weight} = \text{Volume} \times \text{Weight per gallon} \] \[ \text{Total weight} = (6.6 \times 10^5 \text{ gallons}) \times (8.3 \text{ lb/gallon}) \] We can calculate: \[ 6.6 \times 8.3 = 54.78 \] Therefore, \[ \text{Total weight} = 54.78 \times 10^5 \text{ lb} \]

4. Convert to scientific notation: We need to express this value in proper scientific notation: \[ 54.78 \times 10^5 = 5.478 \times 10^6 \text{ lb} \]

So, the approximate weight of the water in an Olympic-sized swimming pool is: \[ \boxed{5.478 \times 10^6 \text{ lb}} \]

Answer 2

u sure

Answer 3

Yes, let's confirm the calculations step by step.

1. Volume of the Olympic-sized swimming pool:

   • The provided volume is \(6.6 \times 10^5\) gallons.

2. Weight of water per gallon:

   • Each gallon of water weighs approximately 8.3 pounds.

3. Total weight calculation:

   • To find the total weight of all the water in the pool, we multiply the volume by the weight per gallon: \[ \text{Total weight} = \text{Volume} \times \text{Weight per gallon} = (6.6 \times 10^5 \text{ gallons}) \times 8.3 \text{ lb/gallon} \]
   • First, we perform the multiplication of the numerical values: \[ 6.6 \times 8.3 = 54.78 \]

4. Putting it all together:

   • Now we multiply this by \(10^5\): \[ \text{Total weight} = 54.78 \times 10^5 \text{ lb} \]
   • In scientific notation, it is proper to express it as: \[ 54.78 \times 10^5 = 5.478 \times 10^6 \text{ lb} \]

Thus, the calculations are correct, and the final answer, which is the approximate weight of the water in an Olympic-sized swimming pool, is indeed: \[ \boxed{5.478 \times 10^6 \text{ lb}} \]

If there's anything specific you'd like me to clarify further, feel free to ask!