A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105

Question

gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses

5.478×106
lb.
5 point 4 7 8 times 10 to the 6th power lb.

54.78×105
lb.
54 point 7 8 times 10 to the 5th power lb.

5.478×105
lb.
5 point 4 7 8 times 10 to the 5th power lb.

54.78×106
lb.

Answer 1

To find the approximate weight of the water in an Olympic-sized swimming pool, you can multiply the number of gallons the pool holds by the weight of a gallon of water.

Given:

• Weight of water per gallon = 8.3 lb
• Volume of the Olympic-sized swimming pool = $6.6\times {10}^5$ gallons

Now, calculate the total weight:

$$\text{Weight}=\text{Volume}\times \text{Weight per gallon}=(6.6\times {10}^5,\text{gallons})\times (8.3,\text{lb/gallon})$$

Calculating this:

$$\text{Weight}=6.6\times 8.3\times {10}^5,\text{lb}$$

Calculating $6.6\times 8.3$:

$$6.6\times 8.3=54.78$$

Now substitute back into the equation:

$$\text{Weight}=54.78\times {10}^5,\text{lb}$$

Now convert $54.78\times {10}^5$ into scientific notation. $54.78$ can be rewritten as $5.478\times {10}^1$:

$$54.78\times {10}^5=5.478\times {10}^1\times {10}^5=5.478\times {10}^6$$

Thus, the approximate weight of the water in an Olympic-sized swimming pool is:

$$\boxed{{\displaystyle 5.478\times {10}^6\text{ lb}}}$$