To find the approximate weight of the water in an Olympic-sized swimming pool, you can multiply the number of gallons the pool holds by the weight of a gallon of water.
Given:
- Weight of water per gallon = 8.3 lb
- Volume of the Olympic-sized swimming pool = \(6.6 \times 10^5\) gallons
Now, calculate the total weight:
\[ \text{Weight} = \text{Volume} \times \text{Weight per gallon} = (6.6 \times 10^5 , \text{gallons}) \times (8.3 , \text{lb/gallon}) \]
Calculating this:
\[ \text{Weight} = 6.6 \times 8.3 \times 10^5 , \text{lb} \]
Calculating \(6.6 \times 8.3\):
\[ 6.6 \times 8.3 = 54.78 \]
Now substitute back into the equation:
\[ \text{Weight} = 54.78 \times 10^5 , \text{lb} \]
Now convert \(54.78 \times 10^5\) into scientific notation. \(54.78\) can be rewritten as \(5.478 \times 10^1\):
\[ 54.78 \times 10^5 = 5.478 \times 10^1 \times 10^5 = 5.478 \times 10^{6} \]
Thus, the approximate weight of the water in an Olympic-sized swimming pool is:
\[ \boxed{5.478 \times 10^6 \text{ lb}} \]