A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6 × 105

gallons. What is the approximate weight of the water in an Olympic-sized swimming pool?(1 point)
Responses

1 answer

To find the approximate weight of the water in an Olympic-sized swimming pool, we can multiply the number of gallons the pool holds by the weight of a gallon of water.

Given:

  • Weight of a gallon of water = 8.3 lb
  • Volume of an Olympic-sized swimming pool = 6.6 × 10^5 gallons

Now, we can calculate the total weight:

\[ \text{Total weight} = \text{Volume of pool} \times \text{Weight per gallon} \] \[ \text{Total weight} = 6.6 \times 10^5 \text{ gallons} \times 8.3 \text{ lb/gallon} \]

Now performing the multiplication:

\[ 6.6 \times 8.3 = 54.78 \] \[ \text{Total weight} = 54.78 \times 10^5 \text{ lb} = 5.478 \times 10^6 \text{ lb} \]

Therefore, the approximate weight of the water in an Olympic-sized swimming pool is:

5.48 million pounds (or about 5.5 million pounds).