F(x) = 3*2^x.
F(-2) = 3 * 2^-2 = 0.75.
F(-1) = 3 * 2^-1 = 1.50.
F(0) = 3 * 2^0 = 3.0.
F(1) = 3 * 2^1 = 6.0
So when x is increased by 1, F(x) doubles. This is normal behavior for
base 2 numerals.
)a function f is defined as f(x) = 3*2^x
describe the end behavior of f, please describe in detail how you got the answer and explain your abbreviations.
1 answer