F = k Q1 2/d^2
k is about 9 * 10^9
the force is between a plus charge and a negative charge so attraction
0.460 = 9*10^9 * 8.85*10^-6 * 3.22*10-6 / d^2
d^2 = (9*8.85* 3.22 / 0.46) * 10^-9 Newtons
d^2 = 558 *10^-9 = 55.8 *10^-10
d = 7.47 *10^-5 meters
A force of 0.460 N exists between a positive charge of 8.50 10-6 C and a negative charge of -3.22 10-6 C. What distance separates the charges?
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