So the negative force must be creating a field of 1.10E5 N/C in the opposite direction.
1.10E5=k (.1C)/distance^2
A positive charge of 1.100ƒÊ C is located in a uniform field of 1.10�~105 N/C. A negative charge of -0.100ƒÊ C is brought near enough to the positive charge that the attractive force between the charges just equals the force on the positive charge due to the field. How close are the two charges?
3 answers
so would the answer be positive?
Huh? The question asks for a distance.