Asked by joel

A flywheel is making 180 r.p.m. and after 20 seconds it is running at 140 r.p.m. How many revolutions
will it make, and what time will elapse before it stops, if the retardation is uniform ?

Answers

Answered by Henry
V1=180rev/min * 6.28rad/rev * 1min/60s =
18.84 Rad/s.

V2 = 140/180 * 18.84 = 14.65 Rad/s.

a = (V2-V1)/t = (14.65-18.84)/20 = -0.209 Rad/s^2.

b. V3 = V1 + a*t = 0
t = -V1/a = -18.84/-0.209 = 90 s. To
stop.

a. V3^2 = V1^2 + 2a*d = 0
d = -V1^2/2a = -(18.84^2)/-0.418 = 849.2
Radians.

849.2Rad * 1rev/6.28Rad = 135.2 rev.
before it stops.





Answered by shadab
ans required
Answered by rafi
angular distance also can b found by s= (vi+vf) x t and the devided by 2
Answered by Mangwana
thanks
Answered by Mangwana
thanks
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