A flowerpot falls from a window sill 28.4 m

above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s2 .
Answer in units of m/s

2 answers

Initial velocity, (u), is given, so is acceleration, (g), so is the distance (s), 28.4m.

Use v^2=u^2+2as and solve for v.
23.4
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