A flowerpot falls from a window sill 27.7 m

above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s
2
.
Answer in units of m/s.

1 answer

Ok I'am new to Physics so I am not 100% sure of answer but it should be 23.3 m/s downwards or in negative direction (like -23.3 m/s). assuming it was at rest at starting!!!

got this using

Vf^2= Vi^2 + 2ad
Vf^2= 0 + 2*(-9.8)(-27.7m)

Vf= sqrt(542.92)

Vf= 23.3 m/s downwards!

(first time answering question on jiskha!)
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