A first order reaction and a separate second order reaction both have the same rate of reaction. What is the effect on the rate of reaction for each reaction if the concentrations of reactants in both reactions are halved?

Answer 1

rate 1 = k(A) = k(1/2) = 1/2 rate
rate 2 = k(A)^2 = k(1/2)^2 = 1/4 rate

Answer 2

thanks! but do you mind explaining it a bit to me?