a). rate = k(NO2)^2
b). (1/2)^2 = ??
c). Where is CO in the rate equation? I don't see it although I could have written the answer to a as rate = (NO2)2(CO)o>/>
The reaction of CO(g) + NO(g) is second-order in NO2 and zero-order in CO at temperatures less than 500K.
(a) Write the rate law for the reaction.
(b) How will the reaction rate change if the NO2 concentration is halved?
(c) How will the reaction rate change is the concentration of CO is doubled?
2 answers
typo.
rate = (NO)2(CO)o
rate = (NO)2(CO)o
2 answers