If the hose elevation angle remains 31.5 degrees, the maximum height obtained for the water stream is
H = (Vo sin31.5)^2/(2g)
= 8.22 m
The stream reaches that height when the distance from the building is
H cos31.5 = 7.01 m
A fire hose ejects a stream of water at an angle of 31.5 ° above the horizontal. The water leaves the nozzle with a speed of 24.3 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?
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