A fire hose ejects a stream of water at an angle of 32.2 ° above the horizontal. The water leaves the nozzle with a speed of 26.5 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

Answer 1

Vo = 26.5m/s[32.2o].
Xo = 26.5*cos32.2 = 22.4 m/s.
Yo = 26.5*sin32.2 = 14.1 m/s

Y = Yo + g*Tr = 0 @ max. ht.
Tr = -Yo/g = -14.1/-9.8 = 1.44 s. =
Rise time.

D = Xo * Tr = 22.4m/s * 1.44s. = 32.3 m.