Asked by Jeremy
A fire hose 10 cm in diameter delivers water at the rate of 23 kg/s. The hose terminates in a nozzle 3.1 cm in diameter.
(a) What is the flow speed in the hose?
(b) What is the flow speed in the nozzle?
(a) What is the flow speed in the hose?
(b) What is the flow speed in the nozzle?
Answers
Answered by
drwls
(a) The volume flow rate Q is the mass flow rate divided by the density.
Q = 23/1000 = 0.023 m^3/s
Q = V*A, where A is the cross sectinal area, (pi/4)*D^2 = 10^-2 m^2
and V is the flow speed
V = .023/10^-2 = 2.3 m/s
(b) Q remains contant in the nozzle, but V increases because of the reduction in A. A is reduced by a factor (10/3.1)^2 = 10.4. V increases by the same factor.
Q = 23/1000 = 0.023 m^3/s
Q = V*A, where A is the cross sectinal area, (pi/4)*D^2 = 10^-2 m^2
and V is the flow speed
V = .023/10^-2 = 2.3 m/s
(b) Q remains contant in the nozzle, but V increases because of the reduction in A. A is reduced by a factor (10/3.1)^2 = 10.4. V increases by the same factor.
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