A fire hose ejects a stream of water at an angle of 33.4 ° above the horizontal. The water leaves the nozzle with a speed of 20.1 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?

Answer 1

v = Vi - 9.81 t
at top v = 0
t = Vi/9.81 at top

Vi = 20.1 sin 33.4 = 11.1
so t = 11.1/9.81 = 1.13 seconds at top

how far horizontal in 1.13 seconds?

u = 20.1 cos 33.4 = 16.8 m/s

16.8 m/s * 1.13 s = 19 meters