so, the radius of the wheel is 15 m
...(31 - 1) / 2
when the altitude is 25 m, the car is 9 m above the center
... 25 - 15 - 1
using Pythagoras,
... hypotenuse (radius) is 15 m
... vertical side is 9 m
... horizontal side is ?
HINT (a big one)
... it's a Pythagorean triple, 3-4-5
a ferris wheel is elevated 1 meter above ground. When car reaches the highest point of the Ferris wheel, it's altitude from ground level is 31 metres. How far away from the center, horizontally, is the car when it is at an altitude of 25 meters?
5 answers
x2 + (y - 16)2 = 225
x2 + (25 + 16) = 225
x2 + 81 = 225
x2 = 225 - 81
x2 = 144 -> squared 144 to illiminate the square in
x2
so.. x = 12
x2 + (25 + 16) = 225
x2 + 81 = 225
x2 = 225 - 81
x2 = 144 -> squared 144 to illiminate the square in
x2
so.. x = 12
Paano nakuha ang 16
How did you get the number 16?
A ferris wheel is elevated 1 m above ground. When a car reaches the highest point on the
ferris wheel, its altitude from ground level is 31 m. How far away from the center,
horizontally, is the car when it is at an altitude of 25 m?
ferris wheel, its altitude from ground level is 31 m. How far away from the center,
horizontally, is the car when it is at an altitude of 25 m?