A Ferris wheel is 40 meters in diameter and boarded from a platform that is 1 meter above the ground. The six o'clock position on the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 12 minutes. How much of the ride, in minutes and seconds, is spent higher than 25 meters above the ground? Round to the nearest second.

1 answer

start with y = sin(x)

40 meters in diameter
means the amplitude is 40/2 = 20
y = 20 sin(x)

boarded from a platform that is 1 meter above the ground.
means the minimum is at y=1, so
y = 21 - 20sin(x)

six o'clock position on the Ferris wheel is level with the loading platform
That means that the minimum is at t=0, so
y = 21 - cos(x)

1 full revolution in 12 minutes
cos(kx) has period 2π/k, so k = π/6
y = 21 - 20cos(π/6 x)

so now just solve
21 - 20cos(π/6 x) > 25