A ferris wheel is elevated 1 meter above ground. When car reaches the highest point of the ferris wheel it's altitude from ground level is 31 meters. How far away from the center,horizontally, is the car it is at an altitude of 25 meters?
3 answers
Since when is math (geometry?) called "Cruz"?
"Ferris wheel is elevated 1 metre above ground"
means that the lowest point is 1 metre above ground. (Draw a sketch to show that).
The highest point is 31 m. above ground, so the diameter is (31-1)=30m, and radius = 30m/2=15m. (Mark that on your sketch).
The centre C is therefore 15+1=16m above ground. (mark centre C on your sketch, draw a radius and mark 15m).
At an altitude of 25m (above ground), it is (25-16)=9m above the centre of the wheel.
Mark the point as A on your sketch. Join C and A and mark radius AC as 15m.
Draw a horizontal radius below A, and drop a perpendicular from A to the horizontal radius, meeting at B.
Mark B on the sketch.
Now triangle ABC is a right triangle, right-angled at B.
AB=9m, AC=15m.
Use Pythagoras theorem to find the horizontal distance between B and C.
BC=√(15²-9²)
= ?
means that the lowest point is 1 metre above ground. (Draw a sketch to show that).
The highest point is 31 m. above ground, so the diameter is (31-1)=30m, and radius = 30m/2=15m. (Mark that on your sketch).
The centre C is therefore 15+1=16m above ground. (mark centre C on your sketch, draw a radius and mark 15m).
At an altitude of 25m (above ground), it is (25-16)=9m above the centre of the wheel.
Mark the point as A on your sketch. Join C and A and mark radius AC as 15m.
Draw a horizontal radius below A, and drop a perpendicular from A to the horizontal radius, meeting at B.
Mark B on the sketch.
Now triangle ABC is a right triangle, right-angled at B.
AB=9m, AC=15m.
Use Pythagoras theorem to find the horizontal distance between B and C.
BC=√(15²-9²)
= ?
12 m
1 answer