A diver running 2.4 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below. How high was the cliff?

Answer 1

The horizontal distance does not change the time it takes to fall through the height of the cliff. It's there probably to throw you off, or there's a second part of the question.

What is important is the initial velocity is horizontal, so the vertical component, u, is zero.

vertical drop
S = ut+(1/2)gt²
= 0 + (1/2)(9.8)*2.6²
=?

Answer 2

0.72