A diver running 1.89 m/s dives out horizontally from the edge of a vertical cliff and 2.88 s later reaches the water below. How high was the cliff.

(in m)

1 answer

h = Vo*t + 0.5g*t^2

Vo = 0
t = 2.88 s.
g = 9.8 m/s^2
Solve for h.