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A damp washcloth is hung over the edge of a table to dry. Thus, part (mass = mon) of the washcloth rests on the table and part...Asked by twill
A damp washcloth is hung over the edge of a table to dry. Thus, part (mass = mon) of the washcloth rests on the table and part (mass = moff) does not. The coefficient of static friction between the table and the washcloth is 0.350. Determine the maximum fraction [moff/(mon + moff)] that can hang over the edge without causing the whole washcloth to slide off the table
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Answered by
bobpursley
friction force=masson*.350g
force pulling=mass0ff*g
forcepulling=frictionforce
moff*g=.350Mon*g
so massoff=.350mon
so the fraction must be massoff/(mon+moff)
= .350mo/(mo*1.35)=.35/1.35
check that.
force pulling=mass0ff*g
forcepulling=frictionforce
moff*g=.350Mon*g
so massoff=.350mon
so the fraction must be massoff/(mon+moff)
= .350mo/(mo*1.35)=.35/1.35
check that.
Answered by
twill
thank you!
Answered by
Jessie
How did you get 1.35?
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