Asked by Tiffany
                A damp washcloth is hung over the edge of a table to dry. Thus, part (mass = mon) of the washcloth rests on the table and part (mass = moff) does not. The coefficient of static friction between the table and the washcloth is 0.395. Determine the maximum fraction [moff/mtotal] that can hang over the edge without causing the whole washcloth to slide off the table.
            
            
        Answers
                    Answered by
            drwls
            
    Net force down = static friction force ,because there will be a balance of tension forces at the edge. 
moff*g = (mtot-moff)*g*(0.395)
(mtot/moff) -1 = 1/0.395 = 1.532
mtot/moff = 2.532
moff/mtot = 0.395
    
moff*g = (mtot-moff)*g*(0.395)
(mtot/moff) -1 = 1/0.395 = 1.532
mtot/moff = 2.532
moff/mtot = 0.395
                    Answered by
            bill
            
    0.395
    
                    Answered by
            Doesn't matter
            
    that is wrong
    
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