To find the number of feet the diver is above the ocean at 2 seconds, we need to evaluate the formula 75 - 16t^3, where t is the time in seconds.
Plugging in t = 2 into the formula, we get:
75 - 16(2)^3
75 - 16(8)
75 - 128
-53
Therefore, the diver is 53 feet above the ocean after 2 seconds.
A competitive cliff diver jumps from a height of 75 feet. Find the number of foot the diver is above the ocean in 2 seconds Evaluate for t = 2 by using the formula 75 - 16t ^ 3 where is time in seconds (1 point)
1 answer