To find the number of feet the diver is above the ocean at \( t = 2 \) seconds, we can plug \( t = 2 \) into the formula:
\[ h(t) = 75 - 16t^2 \]
Substituting \( t = 2 \):
\[ h(2) = 75 - 16(2^2) \]
Calculating \( 2^2 \):
\[ 2^2 = 4 \]
Now substitute this back into the equation:
\[ h(2) = 75 - 16 \times 4 \]
Calculating \( 16 \times 4 \):
\[ 16 \times 4 = 64 \]
Now substitute this value back into the equation:
\[ h(2) = 75 - 64 \]
Finally, perform the subtraction:
\[ h(2) = 11 \]
Thus, the diver is 11 feet above the ocean after 2 seconds.