To find the number of feet the diver is above the ocean after 2 seconds, we'll use the formula given:
\[ h(t) = 75 - 16t^2 \]
where \( h(t) \) is the height in feet and \( t \) is the time in seconds.
We need to evaluate \( h(2) \):
\[ h(2) = 75 - 16(2^2) \]
Calculating \( 2^2 \):
\[ 2^2 = 4 \]
Now substituting that back into the equation:
\[ h(2) = 75 - 16(4) \]
Calculating \( 16(4) \):
\[ 16 \times 4 = 64 \]
Now substituting that back into the equation:
\[ h(2) = 75 - 64 \]
Finally, subtracting gives:
\[ h(2) = 11 \]
Therefore, the diver is 11 feet above the ocean after 2 seconds.