A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a TOTAL of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 300 cars and trucks.
How many CARS did Dealership A sell?
4 answers
are you sure??
Apologies for the confusion. Let's solve the equations again to find the correct answer.
The equations we have are:
C + T = 225 ........(equation 1)
2C + 0.5T = 300 .......(equation 2)
To make equation 2 simpler, let's multiply it by 2 to remove the decimal:
4C + T = 600 .......(equation 3)
Now, we can subtract equation 1 from equation 3:
(4C + T) - (C + T) = 600 - 225
3C = 375
C = 375/3
C = 125
Therefore, Dealership A sold 125 cars.
The equations we have are:
C + T = 225 ........(equation 1)
2C + 0.5T = 300 .......(equation 2)
To make equation 2 simpler, let's multiply it by 2 to remove the decimal:
4C + T = 600 .......(equation 3)
Now, we can subtract equation 1 from equation 3:
(4C + T) - (C + T) = 600 - 225
3C = 375
C = 375/3
C = 125
Therefore, Dealership A sold 125 cars.
Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
If Dealership B sold half as many trucks as Dealership A, and Dealership A sold T trucks, then Dealership B sold T/2 trucks.
In this case, we have already found that Dealership A sold 125 cars (C = 125). To find the number of trucks sold by Dealership A, we can substitute this value into equation 1:
125 + T = 225
T = 225 - 125
T = 100
So, Dealership A sold 100 trucks.
Since Dealership B sold half as many trucks as Dealership A, Dealership B must have sold 100/2 = 50 trucks.
In this case, we have already found that Dealership A sold 125 cars (C = 125). To find the number of trucks sold by Dealership A, we can substitute this value into equation 1:
125 + T = 225
T = 225 - 125
T = 100
So, Dealership A sold 100 trucks.
Since Dealership B sold half as many trucks as Dealership A, Dealership B must have sold 100/2 = 50 trucks.
1 answer