a company owns only cars and trucks. The sum of the cars and trucks owned by the company is 60. One sixh of the red and one half of the trucks are red. If there are twice as many red trucks as red cars, how many cars are not red?

Question

A- 6
B- 12
C-24
D-30
C- Its not there

I think its D, show process please. thank you

Answer 1

is it really "1/6 of the red"?

Answer 2

c=cars
t=trucks
rt=red trucks
rc=red cars

t+c=60
60-t=c
rt=2rc
since red trucks are twice as many as red cars
but
rt= 1/2 t
rc= 1/6 c

1/2 t=2(1/6 x c)
1/2 t =2(1/6 x (60-t))
1/2 t = 1/3 (60-t)
1/2 t = 20- 1/3 t
1/2 t + 1/3 t= 20
5/6 t = 20
t= 24 trucks
so...
60-t= c
c= 36 cars

1/6 of cars are red so..
36 cars x 1/6 = 6 cars are red

36-6 = 30 cars are not red..

checK: red trucks are twice as many as red cars...24/2=2x6 red cars
12=12

Answer 3

the answer is d