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Questions (1)
Given HCL + SrO --- SrCL2 + H20
Calculate the mass of HCl in grams that would react with 4.85 kg SrO.
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Answers (20)
228.40 naut miles..(straight line distancee from port) if your asking for total distance from start its: 238 naut mi.
the answer is d
c=cars t=trucks rt=red trucks rc=red cars t+c=60 60-t=c rt=2rc since red trucks are twice as many as red cars but rt= 1/2 t rc= 1/6 c 1/2 t=2(1/6 x c) 1/2 t =2(1/6 x (60-t)) 1/2 t = 1/3 (60-t) 1/2 t = 20- 1/3 t 1/2 t + 1/3 t= 20 5/6 t = 20 t= 24 trucks
1/x + 1/(x+1)=13 0r 84 x=integer
l=2w-6 2l+2w=28 2(2w-6)+2w=28 4w-12+2w=28 w=6.67 l=7.33
ok but still -2.646 is closer to -8 if the choices given is the only choice
it said 4x is for interior..
it lacks data..
i mean closer to -8 if based from the choices...
triangle have 3 exterior angles = 360 degrees same with its interior with 180 degrees total.. the given is lacking..
D=square root of 2 x side d=282.84 cm or 2.83 meters.. approximately 2
its 5 if 1/3 is left and using a then. 1/3=(1/15)x x=5
question 3: D-irrational num goes forever and dont repeat question 2: is approximately 2..the actual is 2.38... question 1: there is no square root of neg numbers..if there would be.. it will have an imaginary part or in here square root of 7 X i where i
let 1= total job rate=job/min for A=the rate is 1/15 for B= the rate is 1/10 at 4 minutes both were open..so the part of the job done is.. (1/15+1/10)X 4min= 2/3 but after 4 min pipe B closed so A has to work alone...then (1/15)(x) where x is the
maybe you meant 30 deg.
N=newton is equivalent to kgxm/s^2. N=mass x gravitaional acceleration (g) g= 9.81 m/s^2 weight = 120kg x 9.81= 1177.2 N at fulcrum the force from the mass object and the 300 N force from the other end cancels out because of the distance of the 2 forces
S.A=2lw+2hw+2lh where: l=length, w=width, h=height s.A=2(yx3y)+2(yx3y)+2(yxy0 s.a=6y^2+6y^2+2y^2 s.a= 14y^2
10am.-7am.= 3 hours due east from port.. at 10 am it changes direction to the vector specified above..so 2pm-10am= 4 hours from the point where it shifts direction east of north means vehicle pointing north changes direction 57 deg.. to east.. so..3hrs. X
let x be the unknown (50+70+x)/3=55 50+70+x=(55x3) 50+70+x=165 transpose 50 and 70 to the other side and let x remain x= 165-50-70 x=45% check: if each test is 100 items..then.. 50% of 100 for science=50 70% of 100 for english=70 45% of 100 for math= 45
cot(90-A)= -2.40 approximately use arcsinA or 1/sinA =-(12/13) to get the value of A..or use sine graph..to get the answer. cotangent=cosx/sinx.. just input the value of A which is -67.38 to that of formula above with x as (90-A)...
