A CD-Rom starts from rest and undergoes uniform angular acceleration until it reaches 26,000 rpm in 0.25 s. Through what angle does it rotate during this time?

Question

A CD-Rom starts from rest and undergoes uniform angular acceleration until it reaches 26,000 rpm in 0.25 s.  Through what angle does it rotate during this time?

Elena · Answer

f= 26,000 rpm=26000/3600=7.2 rev/s 2πf = εt ε = 2πf/t =2π•7.2/0.25 =176 rad/s² φ = εt²/2 = 176•(0.25)²/2 =5.5 rad