Question

A car starts from rest and undergoes uniform acceleration. During the first second it travels 6 m.
a) what is the car's acceleration?

b) How far will the car travel during the third second?

For a) I used v= v_0 +at
6=0 a*1 so a= 6m/s^2

For b) I used d=d_0 +v_0t + 1/2 at^2
=0 +0(3) + 1/2 (6)(3)^2
= 1/2(6)(9)
=27 m

Did I work out this problem correctly? Thanks in advance for your help.

Answer 1

a is right.
b, find how far it went in two seconds, then in three seconds, and subtract to find how far in the third second.