a) d=1/2 at or a= 2d/t=12m/s^2
b) it went d= 1/2 a t^2 or 1/2 12*2^2 or 24m in two seconds. It went 1/2 12*3^2 or 54m in three seconds. So in the third second, it went 54-24 m.
check my thinkign and math.
A car starts from rest and undergoes uniform acceleration. During the first second it travels 6 m.
a) what is the car's acceleration?
b) How far will the car travel during the third second?
For a) I used v= v_0 +at
6=0 a*1 so a= 6m/s^2
For b) I used d=vt
d=6(3) = 18 m
Did I work out this problem correctly? Thanks in advance for your help.
1 answer
1 answer