A cashier has 26 bills consisting of three times as many ones as fives, one less ten than fives, and the rest twenties. If the value is $120, find how many of each she has.

4 answers

u+f+t = 26
u = 3f
t = f-1
u+5f+10t+20x = 120
Before we try to solve that mess, we know u is a multiple of 5 (because the total is a multiple of 5, and all the other bills are worth multiples of 5). It is also a multiple of 3, so let's say there are 15 ones and 5 fives.
That gives t=6, so there are 6 tens.

Adding up all the values, we see that 15+25+60+20x = 120
That gives us 1 twenty.

You have a typo. It should have said there were one less fives than tens.
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