A cashier has 26 bills consisting of three times as many ones as fives, one less ten than fives, and the rest twenties. If the value is $120, find how many of each she has.

Answer 1

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Answer 2

s = ones , f = fives , t = tens , w = twent

s + f + t + w = 26

s + 5f + 10t + 20w = 120

s = 3f , t = f - 1

the total value is divisible by 5, so the number of ones must be also
... the number of ones must also be divisible by 3

Answer 3

didn't see earlier answers, otherwise i would not have responded

Answer 4

Thank you all very much for your help. it's much appreciated.

Answer 5

X=FIVES
3X=ONES
X-1=TENS
27-5X=TWENTIES (26-(5X-1))
5X+3x+10(x-1)+20(27-5x)=120

Answer 6

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