A cashier has a total of 126 bills, made up of fives and tens. The total value of money is $890. How many ten-dollar bills does the cashier have?

Answer 1

5F+10T=890
F+T=126

multiply the second equation by 5, then subtract the equation from the first.
5F+10T=890
5F+5T=630
then subtract equations
5T=360
T=72
check all that.

Answer 2

Let the fives and tens be represented by 5x +10y=890, x +y =126 solve by elimination . X =74.. y =52