A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.10. If the number of dimes is 1 more than twice the number of nickels, how many of each type of coin does he have?

Answer 1

Ok, your turn.
For the first two, I have given you the equation

What have you done for these last two?
Show me your preliminary steps.

Answer 2

n+d+q=25
n+d(1+2n)+q=4.10

I'm not sure if I am doing this right

Answer 3

no, you are just writing stuff down.

based on what it said:

number of nickels --- x
number of dimes---- 2x+1
number of quarters = 25-(x + 2x+1) = 24 - 3x

now form a "value" equation:
5x + 10(2x+1) + 25(24-3x) = 410