A carpenter has three pieces of timber measuring 2.94m,3.36m and 4.62m.He cuts the timber into pieces of equal lengths. Find the least number of pieces obtained

Answer 1

The least number of pieces obtained would be the length of the greatest common divisor (GCD) of the three lengths of timber.

First, we find the GCD of the three lengths:
GCD(2.94, 3.36, 4.62) = GCD(GCD(2.94, 3.36), 4.62) = GCD(0.42, 4.62) = 0.42

Therefore, the carpenter can cut the timber into pieces of length 0.42m.

To find the least number of pieces obtained, we divide each length by 0.42:
2.94 / 0.42 = 7
3.36 / 0.42 = 8
4.62 / 0.42 = 11

Therefore, the carpenter can obtain 7, 8, or 11 equal length pieces, depending on how he chooses to cut them.