1/2 m vf^2+328*distance=work done
but distance=avgspeed*time=12/2*12.2
so calculate work done. Now divide by time, and you have power.
A car with a mass of 1200 kg kg starts from
rest and accelerates to a speed of 12 m/s in
12.2 s. Assume that the force of resistance
remains constant at 328 N during this time.
What is the average power developed by
the car’s engine?
Answer in units of W.
1 answer