A car starts from rest and accelerates unifomly at 3m/s^2. A second car starts from rest 6 seconds later at the same point and accelerates uniformly at 5m/s^2. How long does it take the second car to over take the first car?

Answer 1

Solve this equation for t:

(3/2) t^2 = (5/2)(t-6)^2

You should get an equation of the form
at^2 + bt + c = 0.

Take the root that is t>6