A cannon ball is fired horizontally from a cannon that is 40.7m above the ground. The initial velocity of the cannon ball is 234m/s. How much time does the cannon ball spend in the air?

Answer 1

how much time does it take to fall?
h=1/2 g t^2
t=sqrt(2*40.7/9.8) do that.
Now, how far does it go horizontally?
distance=234m/s * timeinAir

Answer 2

t= sqrt (8.306) = 2.88s
d= 234m/s * 2.88s = 674.40m

Thanks!