Asked by James
A cannon is fired from the ground at an angle of 30 degrees. It is being shot an an initial velocity of 200m/s. What is the maximum height of the cannon ball? How fat will the cannon ball travel before it hits the ground
Answers
Answered by
Steve
the vertical speed is 200 sin30 = 100 m/s
So, the height is
h(t) = 100t - 4.9t^2
As you recall from algebra I, the vertex of the parabola is at t = -b/2a, which in this case is 100/9.8
So, plug that in to get the max height.
The ball is in the air twice that long, and you know the horizontal speed is 200 cos30, so just multiply speed*time to get distance.
So, the height is
h(t) = 100t - 4.9t^2
As you recall from algebra I, the vertex of the parabola is at t = -b/2a, which in this case is 100/9.8
So, plug that in to get the max height.
The ball is in the air twice that long, and you know the horizontal speed is 200 cos30, so just multiply speed*time to get distance.
Answered by
jimson
what is the answer to my question?
Answered by
Erika
A canon was fired with a muzzle velocity of 100 m/s, mounted at an angle of 30 degrees above the ground.
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