Question

A cannon is fired from the ground at an angle of 30 degrees. It is being shot an an initial velocity of 200m/s. What is the maximum height of the cannon ball? How fat will the cannon ball travel before it hits the ground

Answer 1

the vertical speed is 200 sin30 = 100 m/s

So, the height is

h(t) = 100t - 4.9t^2

As you recall from algebra I, the vertex of the parabola is at t = -b/2a, which in this case is 100/9.8

So, plug that in to get the max height.

The ball is in the air twice that long, and you know the horizontal speed is 200 cos30, so just multiply speed*time to get distance.

Answer 2

what is the answer to my question?

Answer 3

A canon was fired with a muzzle velocity of 100 m/s, mounted at an angle of 30 degrees above the ground.