Asked by Victoria
A cannon ball is fired at 50 m/s at a 37 degree angle above the horizontal. Calculate the time the cannon ball in the air, calculate how high it rises and calculate how far from the cannon the ball lands?
Answers: 6.14 s, 46.2 m, 245.2 m
Answers: 6.14 s, 46.2 m, 245.2 m
Answers
Answered by
Alex
G:
Vi = 50m/s
Degree = 37
U: Vy, Vx, Dy, Dx, T
E:
Vy = Vi(Sin(θ)),
Vx = Vi(Cos(θ),
Dy = Vy(1/2)(t) + 1/2(a)(1/2t^2)
Dx = Vx(t) (Because the speed is constant)
t = 6.14 s, h = 46.2, Δx = 245.2 m
Vi = 50m/s
Degree = 37
U: Vy, Vx, Dy, Dx, T
E:
Vy = Vi(Sin(θ)),
Vx = Vi(Cos(θ),
Dy = Vy(1/2)(t) + 1/2(a)(1/2t^2)
Dx = Vx(t) (Because the speed is constant)
t = 6.14 s, h = 46.2, Δx = 245.2 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.