G:
Vi = 50m/s
Degree = 37
U: Vy, Vx, Dy, Dx, T
E:
Vy = Vi(Sin(θ)),
Vx = Vi(Cos(θ),
Dy = Vy(1/2)(t) + 1/2(a)(1/2t^2)
Dx = Vx(t) (Because the speed is constant)
t = 6.14 s, h = 46.2, Δx = 245.2 m
A cannon ball is fired at 50 m/s at a 37 degree angle above the horizontal. Calculate the time the cannon ball in the air, calculate how high it rises and calculate how far from the cannon the ball lands?
Answers: 6.14 s, 46.2 m, 245.2 m
1 answer
1 answer