Question
A projectile is fired from ground level with an initial velocity of 50m/s and an initial angle of 30degree. Assuming g= 9.8 m/s*2, find:
(a) The projectile total time of flight.
(b) The maximum height attained
(c) The total horizontal traveled
(d) The final horizontal and vertical velocities just before it hits the ground
(a) The projectile total time of flight.
(b) The maximum height attained
(c) The total horizontal traveled
(d) The final horizontal and vertical velocities just before it hits the ground
Answers
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h = 50*sin30° t - 4.9t^2
= 25t - 4.9t^2
= t(25-4.9t)
(a) h=0 at t=0 and t=5.10
(b) max height achieved at t = 25/9.8 = 2.55
h(2.55) = 31.9
(c) x = 5.10 * 50 * cos 30° = 220.8
(d) speeds same as at launch
= 25t - 4.9t^2
= t(25-4.9t)
(a) h=0 at t=0 and t=5.10
(b) max height achieved at t = 25/9.8 = 2.55
h(2.55) = 31.9
(c) x = 5.10 * 50 * cos 30° = 220.8
(d) speeds same as at launch