A brand of cereal had

Question

\[1.2\] milligrams
\[(\text{mg})\] of iron per serving. Then they changed their recipe so they had
\[1.8\,\text{mg}\] of iron per serving.
What was the percent increase in iron?

Answer 1

To calculate the percent increase, you can use the following formula:

\[ \text{Percent Increase} = \frac{\text{New Amount} - \text{Original Amount}}{\text{Original Amount}} \times 100\% \]

Let's apply this formula using the original iron content of 1.2 mg and the new iron content of 1.8 mg.

\[ \text{Percent Increase} = \frac{1.8\, \text{mg} - 1.2\, \text{mg}}{1.2\, \text{mg}} \times 100\% \]

\[ \text{Percent Increase} = \frac{0.6\, \text{mg}}{1.2\, \text{mg}} \times 100\% \]

\[ \text{Percent Increase} = 0.5 \times 100\% \]

\[ \text{Percent Increase} = 50\% \]

Thus, the percent increase in iron is 50%.