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A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point) Responses 80 N 80 N 370 N 370 N 70 N 70 N 380 N

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To find the net force acting on the boy, we can use the following equation:

\[ \text{Net Force} = \text{Applied Forces} - \text{Friction/Drag Forces} \]

  1. The boy exerts a force of 300 N.
  2. His friend pulls him with a force of 75 N.
  3. The drag and friction force amounts to 5 N.

Now, let's calculate the total applied force:

\[ \text{Total Applied Force} = 300 , \text{N} + 75 , \text{N} = 375 , \text{N} \]

Next, we subtract the friction and drag force:

\[ \text{Net Force} = 375 , \text{N} - 5 , \text{N} = 370 , \text{N} \]

Thus, the magnitude of the net force acting on the boy is 370 N.