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A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point) Responses 80 N 80 N 370 N 370 N 70 N 70 N 380

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To determine the net force acting on the boy, we need to consider all the forces acting on him:

  1. The boy exerts a force of 300 N.
  2. His friend pulls him with a force of 75 N.
  3. There is a drag and friction force acting against him of 5 N.

The total force exerted by the boy and his friend is: \[ F_{\text{applied}} = 300, \text{N} + 75, \text{N} = 375, \text{N} \]

Now, we subtract the opposing force (drag and friction): \[ F_{\text{net}} = F_{\text{applied}} - F_{\text{friction}} \] \[ F_{\text{net}} = 375, \text{N} - 5, \text{N} = 370, \text{N} \]

Therefore, the magnitude of the net force acting on him is 370 N.